2 条题解
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0
60分代码:
#include <bits/stdc++.h> using namespace std; constexpr int N = 1e5 + 5; int a[N], f[N]; int main() { int n; scanf("%d", &n); for (int i = 1; i <= n; i++) scanf("%d", &a[i]); memset(f, 0, sizeof(f)); for (int i = 1; i <= n; i++) { f[0] = f[0] + (a[i] == 0 ? 1 : 0); for (int j = i; j >= 1; j--) f[j] = max(f[j] + (a[i] == i - j ? 1 : 0), f[j - 1]); } int ans = 0; for (int i = 1; i <= n; i++) ans = max(ans, f[i]); printf("%d\n", ans); return 0; } -
0
60分代码:
#include <bits/stdc++.h> using namespace std; constexpr int N = 1e5 + 5; int a[N], f[N]; int main() { int n; scanf("%d", &n); for (int i = 1; i <= n; i++) scanf("%d", &a[i]); memset(f, 0, sizeof(f)); for (int i = 1; i <= n; i++) { f[0]=f[0] + (a[i] == 0 ? 1 : 0); for (int j = i; j >= 1; j--) f[j] = max(f[j] + (a[i] == i - j ? 1 : 0), f[j - 1]); } int ans=0;for(int i=1;i<=n;i++) ans=max(ans,f[i]); printf("%d\n", ans); return 0; }
- 1
信息
- ID
- 2762
- 时间
- 500ms
- 内存
- 256MiB
- 难度
- 7
- 标签
- 递交数
- 22
- 已通过
- 7
- 上传者