1 条题解
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0

#include <bits/stdc++.h> using std::cin; using std::cout; void work() { int n, V, L, R, t, ans, fl, cost; cin >> V >> L >> R >> t >> n, V /= n; for (n = ans = 1; n > 0; ++ans, n *= 2) { if (R - L <= (long long)n * t) {cout << ans - 1 << '\n'; return;} if ((fl = R - t - V / ans) > 0) cost = (fl + t - 1) / t, n -= cost, R -= cost * t; } cout << "impossible\n"; } int main() { int T; std::ios::sync_with_stdio(false), cin.tie(NULL); for (cin >> T; T; --T) work(); return 0; }
- 1
信息
- ID
- 5777
- 时间
- 1000ms
- 内存
- 1028MiB
- 难度
- 10
- 标签
- 递交数
- 1
- 已通过
- 1
- 上传者