1 条题解

  • 0
    @ 2026-7-4 10:41:41

    #include <cstdio>
    #include <iostream>
    using namespace std;
    #define int long long
    const int M = 200005;
    const int inf = 1e18;
    int read()
    {
    	int x=0,f=1;char c;
    	while((c=getchar())<'0' || c>'9') {if(c=='-') f=-1;}
    	while(c>='0' && c<='9') {x=(x<<3)+(x<<1)+(c^48);c=getchar();}
    	return x*f;
    }
    int n,ans,p[M],a[M],b[M],c[M],A[M],B[M],C[M],dp[M],bit[M];
    int lowbit(int x)
    {
    	return x&(-x);
    }
    void add(int x,int y)
    {
    	for(int i=x;i<=n;i+=lowbit(i))
    		bit[i]=min(bit[i],y);
    }
    int ask(int x)
    {
    	int r=inf;
    	for(int i=x;i>0;i-=lowbit(i))
    		r=min(r,bit[i]);
    	return r;
    }
    signed main()
    {
    	n=read();ans=inf;
    	for(int i=1;i<=n;i++)
    	{
    		int x=read();
    		p[x]=i;//the position of person x
    		bit[i]=inf;
    	}
    	for(int i=1;i<=n;i++)
    	{
    		a[i]=read(),b[i]=read(),c[i]=read();
    		A[i]=A[i-1]+a[i];
    		B[i]=B[i-1]+min(a[i],b[i]);
    		C[i]=C[i-1]+min(a[i],c[i]);
    	}
    	for(int i=1;i<=n;i++)
    	{
    		dp[i]=min(B[i-1],ask(p[i])+A[i-1]);
    		add(p[i],dp[i]-A[i]);
    		ans=min(ans,dp[i]+C[n]-C[i]);
    	}
    	printf("%lld\n",ans);
    }
    
    
    • 1

    信息

    ID
    12107
    时间
    2000ms
    内存
    1024MiB
    难度
    10
    标签
    递交数
    1
    已通过
    1
    上传者